Question

find the sum.
\\(\left( \frac{7}{4}x - 5 \
ight) + (2y - 3.5) + \left( -\frac{1}{4}x + 5 \
ight) = \square\\)

Explanation:

Step1: Combine like terms for x

$\frac{7}{4}x + (-\frac{1}{4}x) = (\frac{7}{4} - \frac{1}{4})x = \frac{6}{4}x = \frac{3}{2}x$

Step2: Combine constant terms

$-5 - 3.5 + 5 = (-5 + 5) - 3.5 = 0 - 3.5 = -3.5$

Step3: The term with y remains as is

The term with y is $2y$

Step4: Combine all simplified terms

$\frac{3}{2}x + 2y - 3.5$ (or can also be written as $1.5x + 2y - 3.5$)

Answer:

$\frac{3}{2}x + 2y - 3.5$ (or $1.5x + 2y - 3.5$)