Question

find the solution of the system of equations.\

$$\begin{cases}-x + 3y = -1\\\\x + 4y = 8\\end{cases}$$

\
show your work here\
x =\
y =\
check

Explanation:

Step1: Add the two equations

Add the equations \(-x + 3y = -1\) and \(x + 4y = 8\) together. The \(x\) terms will cancel out:

$$
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$$

Step2: Solve for \(y\)

Divide both sides of \(7y = 7\) by 7:

$$ y = \frac{7}{7} = 1 $$

Step3: Substitute \(y = 1\) into one of the original equations

Let's use the second equation \(x + 4y = 8\). Substitute \(y = 1\) into it:

$$ x + 4(1) = 8 $$

Step4: Solve for \(x\)

Simplify and solve for \(x\):

$$
LATEXBLOCK1
$$

Answer:

\(x = 4\), \(y = 1\)