Question

find the slope of the line represented by the equation below. 10 = -2y + 5x

Explanation:

Step1: Rewrite in slope - intercept form

The slope - intercept form of a line is \(y = mx + b\), where \(m\) is the slope and \(b\) is the y - intercept. We start with the given equation \(10=-2y + 5x\).
First, we want to solve for \(y\). Add \(2y\) to both sides of the equation: \(2y+10 = 5x\).
Then, subtract 10 from both sides: \(2y=5x - 10\).

Step2: Solve for y

Divide each term in the equation \(2y = 5x-10\) by 2.
\(y=\frac{5}{2}x-5\)
In the slope - intercept form \(y = mx + b\), the coefficient of \(x\) is the slope. Here, the coefficient of \(x\) is \(\frac{5}{2}\).

Answer:

\(\frac{5}{2}\)