QUESTION IMAGE
Question
find rs.
rs =
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work it out
Step1: Identify Similar Triangles
From the diagram, \( SP \parallel RQ \) (implied by the red arrows, so by the Basic Proportionality Theorem or AA similarity, \( \triangle TSP \sim \triangle TRQ \)). Let \( RS = x \), so \( TR = TS + SR = 38 + x \). The bases: \( TP = TQ - PQ = 33 - 11 = 22 \), \( TQ = 33 \).
Step2: Set Up Proportion
By similarity, \( \frac{TS}{TR} = \frac{TP}{TQ} \). Substitute values: \( \frac{38}{38 + x} = \frac{22}{33} \). Simplify \( \frac{22}{33} = \frac{2}{3} \), so \( \frac{38}{38 + x} = \frac{2}{3} \).
Step3: Solve for \( x \)
Cross - multiply: \( 3\times38 = 2\times(38 + x) \). \( 114 = 76 + 2x \). Subtract 76: \( 2x = 114 - 76 = 38 \). Divide by 2: \( x = 19 \).
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\( 19 \)