find the real solution of the following radical equation.

\24\sqrt{2b} - 19 = 29\

\b = ?\

Question

find the real solution of the following radical equation.

\24\sqrt{2b} - 19 = 29\

\b = ?\

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "blank_filling_formatter", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [ "Radical Equations", "Solving Radical Equations" ], "new_concepts": [], "current_concepts": [ "Radical Equations", "Solving Radical Equations" ] } ## Isolate the radical term $$ \begin{aligned} 24\sqrt{2b} - 19 &= 29 \ 24\sqrt{2b} &= 29 + 19 \ 24\sqrt{2b} &= 48 \end{aligned} $$ ## Divide by the coefficient $$ \begin{aligned} \sqrt{2b} &= \frac{48}{24} \ \sqrt{2b} &= 2 \end{aligned} $$ ## Square both sides and solve for b $$ \begin{aligned} (\sqrt{2b})^2 &= 2^2 \ 2b &= 4 \ b &= 2 \end{aligned} $$ Find the real solution of the following radical equation. $24\sqrt{2b} - 19 = 29$ $b =$ 2 { "subject": "Mathematics", "question_type": "Fill-in-the-blank", "knowledge_point": [ "Mathematics", "Algebra", "Solving Radical Equations" ] }

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QUESTION IMAGE

Question

Explanation:

Isolate the radical term

Divide by the coefficient

Square both sides and solve for b

Answer: