Question

find the probability using the normal distribution: ( p(z > 2.33) ). use the standard normal distribution table and enter the answer to 4 decimal places.

( p(z > 2.33) = )

Explanation:

Step1: Use the property of normal distribution

We know that \(P(Z > z)=1 - P(Z\leq z)\). Here \(z = 2.33\).

Step2: Look up the value in the standard - normal table

From the standard normal distribution table, for \(z = 2.33\), \(P(Z\leq2.33)=0.9901\).

Step3: Calculate \(P(Z > 2.33)\)

Substitute the value of \(P(Z\leq2.33)\) into the formula \(P(Z > 2.33)=1 - P(Z\leq2.33)\). So \(P(Z > 2.33)=1 - 0.9901\).

Answer:

\(0.0099\)