Question

find a point on the line and the lines slope
y + 1 = -\frac{1}{4}(x + 3)
point on the line:
slope:

Explanation:

Step1: Identify point-slope form

The line is given in $y - y_1 = m(x - x_1)$ form, where $(x_1,y_1)$ is a point on the line, and $m$ is the slope. Rewrite the given equation to match this form:
$y - (-1) = -\frac{1}{4}(x - (-3))$

Step2: Extract the point

From the rewritten equation, $x_1 = -3$ and $y_1 = -1$, so the point is $(-3, -1)$.

Step3: Extract the slope

The coefficient of $(x - x_1)$ is the slope $m = -\frac{1}{4}$.

Answer:

point on the line: $(-3, -1)$
slope: $-\frac{1}{4}$