find f(2) for the piece-wise function.

\f(x) = \begin{cases} -2x + 1, & x \le 1 \\ -x + 2, & x 1 \end{cases}\

$f(2) = ? $

Question

find f(2) for the piece-wise function.

\f(x) = \begin{cases} -2x + 1, & x \le 1 \\ -x + 2, & x > 1 \end{cases}\

$f(2) =  ? $

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "blank_filling_formatter", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [ "Piecewise Functions", "Function Evaluation" ], "new_concepts": [], "current_concepts": [ "Piecewise Functions", "Function Evaluation" ] } ## Determine the correct interval for x = 2 $$ x = 2 \implies 2 > 1 $$ ## Evaluate the corresponding function piece $$ \begin{aligned} f(x) &= -x + 2 \ f(2) &= -2 + 2 \ f(2) &= 0 \end{aligned} $$ Find $f(2)$ for the piece-wise function. $$f(x) = \begin{cases} -2x + 1, & x \le 1 \ -x + 2, & x > 1 \end{cases}$$ $f(2) =$ 0 { "subject": "Mathematics", "question_type": "Fill-in-the-blank", "knowledge_point": [ "Mathematics", "Algebra", "Piecewise Functions" ] }

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QUESTION IMAGE

Question

Explanation:

Determine the correct interval for x = 2

Evaluate the corresponding function piece

Answer: