Question

find the perimeter of this triangle. 120 ft 240 ft 66 ft 56 ft (triangle with sides labeled 20 ft, 12 ft, base 24 ft, height 10 ft)

Explanation:

Step1: Recall Perimeter Definition

Perimeter of a triangle is the sum of all its side lengths.

Step2: Identify Side Lengths

From the triangle, the sides are \( 20 \, \text{ft} \), \( 12 \, \text{ft} \), and \( 24 \, \text{ft} \)? Wait, no—wait, the triangle has a base of \( 24 \, \text{ft} \), one side \( 20 \, \text{ft} \), another side \( 12 \, \text{ft} \)? Wait, no, maybe I misread. Wait, the triangle: let's check. Wait, the height is \( 10 \, \text{ft} \), base \( 24 \, \text{ft} \), and two other sides? Wait, no, the given sides are \( 20 \, \text{ft} \), \( 12 \, \text{ft} \), and \( 24 \, \text{ft} \)? Wait, no, maybe the triangle is a triangle with sides \( 20 \, \text{ft} \), \( 12 \, \text{ft} \), and \( 24 \, \text{ft} \)? Wait, no, let's calculate the perimeter by adding all three sides. Wait, the sides are \( 20 \, \text{ft} \), \( 12 \, \text{ft} \), and \( 24 \, \text{ft} \)? Wait, no, maybe the triangle has sides \( 20 \, \text{ft} \), \( 12 \, \text{ft} \), and \( 24 \, \text{ft} \)? Wait, no, let's add them: \( 20 + 12 + 24 = 56 \)? Wait, no, \( 20 + 12 = 32 \), \( 32 + 24 = 56 \)? Wait, but wait, maybe the triangle is isoceles? No, the given sides: \( 20 \, \text{ft} \), \( 12 \, \text{ft} \), and \( 24 \, \text{ft} \). Wait, let's check the options. The options are \( 120 \), \( 240 \), \( 66 \), \( 56 \). So \( 20 + 12 + 24 = 56 \). Wait, yes, that's one of the options. Wait, maybe I made a mistake. Wait, no, perimeter is sum of all sides. So \( 20 + 12 + 24 = 56 \). Wait, but let's confirm. The triangle has sides \( 20 \, \text{ft} \), \( 12 \, \text{ft} \), and \( 24 \, \text{ft} \). So adding them: \( 20 + 12 + 24 = 56 \, \text{ft} \).

Answer:

\( 56 \, \text{ft} \) (corresponding to the option with \( 56 \, \text{ft} \))