Question

1. find the perimeter of the trapezoid found below. 4x² + 3x - 9 6x - 5 6x² + 7x - 1

Explanation:

Step1: Recall perimeter formula

Perimeter \(P\) of trapezoid is sum of all sides. Let the two un - labeled equal sides be \(a\) and \(a\), and given sides be \(b = 4x^{2}+3x - 9\), \(c=6x - 5\), \(d = 6x^{2}+7x - 1\). Since the two un - labeled sides are equal and one is \(6x - 5\), then \(a = 6x - 5\).

Step2: Calculate sum

\(P=(4x^{2}+3x - 9)+2(6x - 5)+(6x^{2}+7x - 1)\)
\(=4x^{2}+3x - 9 + 12x-10 + 6x^{2}+7x - 1\)
\(=(4x^{2}+6x^{2})+(3x + 12x+7x)+(-9-10 - 1)\)
\(=10x^{2}+22x-20\)

Answer:

\(10x^{2}+22x - 20\)