Question

find the midpoint of the line segment with endpoints p1(3/12, - 5/7) and p2(- 3/12, - 5/7). the midpoint of the line segment is . (simplify your answer. type an ordered pair.)

Explanation:

Step1: Recall mid - point formula

The mid - point formula for two points $(x_1,y_1)$ and $(x_2,y_2)$ is $(\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$. Here $x_1=\frac{7}{12},y_1 =-\frac{5}{7},x_2=-\frac{5}{12},y_2=\frac{7}{7} = 1$.

Step2: Calculate the x - coordinate of the mid - point

$\frac{x_1 + x_2}{2}=\frac{\frac{7}{12}+(-\frac{5}{12})}{2}=\frac{\frac{7 - 5}{12}}{2}=\frac{\frac{2}{12}}{2}=\frac{2}{12}\times\frac{1}{2}=\frac{1}{12}$.

Step3: Calculate the y - coordinate of the mid - point

$\frac{y_1 + y_2}{2}=\frac{-\frac{5}{7}+1}{2}=\frac{-\frac{5}{7}+\frac{7}{7}}{2}=\frac{\frac{- 5 + 7}{7}}{2}=\frac{\frac{2}{7}}{2}=\frac{2}{7}\times\frac{1}{2}=\frac{1}{7}$.

Answer:

$(\frac{1}{12},\frac{1}{7})$