Question

find the midpoint of the line segment with endpoints $p_1(\frac{3}{2},\frac{3}{8})$ and $p_2(-\frac{5}{2},\frac{5}{8})$. the midpoint of the line segment is (simplify your answer. type an ordered pair.)

Explanation:

Step1: Recall mid - point formula

For two points $(x_1,y_1)$ and $(x_2,y_2)$, the mid - point $(x_m,y_m)$ is given by $x_m=\frac{x_1 + x_2}{2}$ and $y_m=\frac{y_1 + y_2}{2}$. Here $x_1=\frac{3}{2}$, $y_1=\frac{3}{8}$, $x_2=-\frac{5}{2}$, $y_2=\frac{5}{8}$.

Step2: Calculate the x - coordinate of the mid - point

$x_m=\frac{\frac{3}{2}+(-\frac{5}{2})}{2}=\frac{\frac{3 - 5}{2}}{2}=\frac{\frac{-2}{2}}{2}=\frac{-1}{2}=-\frac{1}{2}$.

Step3: Calculate the y - coordinate of the mid - point

$y_m=\frac{\frac{3}{8}+\frac{5}{8}}{2}=\frac{\frac{3 + 5}{8}}{2}=\frac{\frac{8}{8}}{2}=\frac{1}{2}$.

Answer:

$(-\frac{1}{2},\frac{1}{2})$