Question

find the lines slope and a point on the line.
$y - 2 = -4(x + 4)$
slope:
point on the line: $(quad,quad)$

Explanation:

Step1: Recall point - slope form

The point - slope form of a line is given by $y - y_1=m(x - x_1)$, where $m$ is the slope of the line and $(x_1,y_1)$ is a point on the line.

Step2: Compare with given equation

The given equation is $y - 2=-4(x + 4)$. We can rewrite $x + 4$ as $x-(-4)$. So, comparing $y - 2=-4(x-(-4))$ with the point - slope form $y - y_1=m(x - x_1)$, we can see that $m=-4$ (this is the slope) and $x_1=-4$ and $y_1 = 2$. So a point on the line is $(-4,2)$.

Answer:

slope: $-4$
point on the line: $(-4,2)$