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2. find the equation of the parabola having its vertex at the origin an…

Question

  1. find the equation of the parabola having its vertex at the origin and symmetrical about the x - axis and passing through the point (-4, - 10). sketch its graph.

Explanation:

Step1: Determine the standard - form of the parabola

Since the parabola is symmetric about the x - axis and has its vertex at the origin, its standard form is $y^{2}=4px$ (if it opens to the right or left).

Step2: Substitute the given point into the equation

Substitute the point $(-4,-10)$ into $y^{2}=4px$. We get $(-10)^{2}=4p\times(-4)$.
So, $100 = - 16p$.

Step3: Solve for $p$

Solve the equation $100=-16p$ for $p$. We have $p=-\frac{100}{16}=-\frac{25}{4}$.

Step4: Write the equation of the parabola

Substitute $p =-\frac{25}{4}$ into $y^{2}=4px$. The equation of the parabola is $y^{2}=4\times(-\frac{25}{4})x=-25x$.

Answer:

The equation of the parabola is $y^{2}=-25x$.