Question

find the equation of the line written in point - slope form with the given slope and passes through the given point. use x as the independent variable. slope = \\(\frac{1}{3}\\) point = (-11, 16)

Explanation:

Step1: Recall point-slope formula

The point-slope form of a line is $y - y_1 = m(x - x_1)$, where $m$ is the slope, and $(x_1, y_1)$ is the given point.

Step2: Substitute given values

Substitute $m = \frac{1}{3}$, $x_1 = -11$, and $y_1 = 16$ into the formula:
$y - 16 = \frac{1}{3}(x - (-11))$

Step3: Simplify the x-term

Simplify the double negative in the parentheses:
$y - 16 = \frac{1}{3}(x + 11)$

Answer:

$y - 16 = \frac{1}{3}(x + 11)$