Question

find the equation of the line with slope = 7 and passing through (7,53). write your equation in the form $y = mx + b$.
$y = \square$
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Explanation:

Step1: Recall the slope - intercept form

The slope - intercept form of a line is $y = mx + b$, where $m$ is the slope and $b$ is the y - intercept. We know that $m = 7$, so the equation of the line is $y=7x + b$.

Step2: Substitute the point into the equation

The line passes through the point $(7,53)$. This means that when $x = 7$, $y = 53$. Substitute $x = 7$, $y = 53$ and $m = 7$ into the equation $y=mx + b$:

$$
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$$

Step3: Solve for $b$

Subtract 49 from both sides of the equation $53=49 + b$:

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$$

Step4: Write the final equation

Now that we know $m = 7$ and $b = 4$, substitute these values into the slope - intercept form $y=mx + b$. We get $y = 7x+4$.

Answer:

$y = 7x + 4$