Question

find the distance d(p1, p2) between the points p1 and p2. p1 = (-2, 3); p2 = (6, 0) d(p1, p2) = □ (type an exact answer, using radicals as needed.)

Explanation:

Step1: Recall distance formula

The distance formula between two points $P_1(x_1,y_1)$ and $P_2(x_2,y_2)$ is $d(P_1,P_2)=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$.
Here $x_1=-2,y_1 = 3,x_2=6,y_2 = 0$.

Step2: Substitute values

$d(P_1,P_2)=\sqrt{(6-(-2))^2+(0 - 3)^2}=\sqrt{(6 + 2)^2+(-3)^2}=\sqrt{8^2+(-3)^2}$.

Step3: Calculate squares and sum

$\sqrt{64 + 9}=\sqrt{73}$.

Answer:

$\sqrt{73}$