Question

find the distance between the points (-4, 4) and (7, 9). round decimals to the nearest tenth. units

Explanation:

Step1: Identify the coordinates

Let \((x_1,y_1)=(-4,4)\) and \((x_2,y_2)=(7,9)\)

Step2: Use the distance formula \(d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\)

Substitute the values: \(d=\sqrt{(7-(-4))^2+(9 - 4)^2}=\sqrt{(7 + 4)^2+(5)^2}=\sqrt{11^2+5^2}\)

Step3: Calculate the squares

\(11^2 = 121\) and \(5^2=25\), so \(d=\sqrt{121 + 25}=\sqrt{146}\)

Step4: Find the square - root and round

\(\sqrt{146}\approx12.1\)

Answer:

\(12.1\)