Question

find the distance, d, of ab. a = (-7, -7) b = (-3, -1) d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2} d = ? round to the nearest te

Explanation:

Step1: Identify coordinates

Let $(x_1,y_1)=(-7,-7)$ and $(x_2,y_2)=(-3,-1)$.

Step2: Substitute into distance formula

$d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}=\sqrt{(-3-(-7))^2+(-1 - (-7))^2}$.

Step3: Simplify expressions inside square - root

First, $-3-(-7)=-3 + 7=4$ and $-1-(-7)=-1 + 7 = 6$. Then $d=\sqrt{4^2+6^2}=\sqrt{16 + 36}$.

Step4: Calculate the sum inside square - root and square - root value

$16+36 = 52$, so $d=\sqrt{52}\approx7.2$.

Answer:

$7.2$