Question

find the distance, d, of ab. a = (-5, 5) b = (5, -5) d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2} d = ? round to the nearest tenth.

Explanation:

Step1: Identify the coordinates

Let $(x_1,y_1)=(-5,5)$ and $(x_2,y_2)=(5, - 5)$.

Step2: Substitute into distance formula

$d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}=\sqrt{(5-(-5))^2+((-5)-5)^2}=\sqrt{(5 + 5)^2+(-10)^2}=\sqrt{10^2+(-10)^2}=\sqrt{100 + 100}=\sqrt{200}$.

Step3: Simplify and round

$\sqrt{200}\approx14.1$.

Answer:

$14.1$