find the distance, d, of $ \overline { a b } $.
$ a = ( 5,4 ) \quad b = ( 14,0 ) $
$ d = $
$ d = \sqrt { ( x _ { 2 } - x _ { 1 } ) ^ { 2 } + ( y _ { 2 } - y _ { 1 } ) ^ { 2 } } $
round to the nearest tenth

Question

Accepted Answer

# Explanation:
## Step1: Identify coordinates
Let $A=(x_1,y_1)=(5,4)$ and $B=(x_2,y_2)=(14,0)$
## Step2: Substitute into distance formula
$$
\begin{align*}
d&=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\
&=\sqrt{(14 - 5)^2+(0 - 4)^2}\
&=\sqrt{9^2+(- 4)^2}\
&=\sqrt{81 + 16}\
&=\sqrt{97}
\end{align*}
$$
## Step3: Calculate the value
$\sqrt{97}\approx9.8$

# Answer:
$9.8$

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QUESTION IMAGE

Question

Explanation:

Step1: Identify coordinates

Step2: Substitute into distance formula

Step3: Calculate the value

Answer: