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if $vec{x}=(3, - 3)$ and $vec{y}=(-2, -2)$, find the difference $vec{x}…

Question

if $vec{x}=(3, - 3)$ and $vec{y}=(-2, -2)$, find the difference $vec{x}-vec{y}$. $vec{x}-vec{y}=langle,,,,,
angle$

Explanation:

Step1: Subtract x - components

Subtract the x - components of the vectors. The x - component of $\vec{x}$ is 3 and of $\vec{y}$ is - 2. So, $3-(-2)=3 + 2=5$.

Step2: Subtract y - components

Subtract the y - components of the vectors. The y - component of $\vec{x}$ is - 3 and of $\vec{y}$ is - 2. So, $-3-(-2)=-3 + 2=-1$.

Answer:

$\langle5,-1
angle$