Question

find the axis of symmetry. f(x) = 3x² + 7 x =

Explanation:

Step1: Recall the formula for the axis of symmetry of a quadratic function.

For a quadratic function in the form \( f(x) = ax^2 + bx + c \), the axis of symmetry is given by the formula \( x = -\frac{b}{2a} \).

Step2: Identify the values of \( a \) and \( b \) from the given function.

In the function \( f(x) = 3x^2 + 7 \), we can rewrite it as \( f(x) = 3x^2 + 0x + 7 \). So, \( a = 3 \) and \( b = 0 \).

Step3: Substitute the values of \( a \) and \( b \) into the formula.

Substituting \( a = 3 \) and \( b = 0 \) into \( x = -\frac{b}{2a} \), we get:

$$ x = -\frac{0}{2 \times 3} $$

Step4: Simplify the expression.

Simplifying \( -\frac{0}{6} \), we get \( x = 0 \).

Answer:

\( x = 0 \)