Question

find the area of a trapezoid with bases 2 ft and 3 ft and height \\( \frac { 1 } { 4 } \\) ft. \\( \frac { 3 } { 8 } \mathrm { ft } ^ { 2 } \\) \\( \frac { 4 } { 5 } \mathrm { ft } ^ { 2 } \\) \\( \frac { 3 } { 4 } \mathrm { ft } ^ { 2 } \\) \\( \frac { 5 } { 8 } \mathrm { ft } ^ { 2 } \\)

Explanation:

Step1: Recall the area formula for a trapezoid

The formula for the area of a trapezoid is \(A=\frac{1}{2}(b_1 + b_2)h\), where \(b_1\) and \(b_2\) are the lengths of the bases and \(h\) is the height.

Step2: Substitute the given values into the formula

Given \(b_1 = 2\) ft, \(b_2=3\) ft, and \(h=\frac{1}{4}\) ft.

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Answer:

\(\frac{5}{8}\text{ ft}^2\)