QUESTION IMAGE
Question
find the area of the indicated region under the standard normal curve.
a. 0.9177
b. 0.0968
c. 0.0823
d. 0.9032
Step1: Find the area to the left of \(z = 0\)
The area to the left of \(z = 0\) in the standard normal curve is \(0.5\).
Step2: Find the area to the left of \(z=-1.30\)
Looking up \(z = - 1.30\) in the standard - normal table, the area to the left of \(z=-1.30\) is \(0.0968\).
Step3: Calculate the area of the shaded region
The area of the shaded region is the area to the left of \(z = 0\) minus the area to the left of \(z=-1.30\). So, \(A=0.5 - 0.0968=0.4032\). Wait, no, actually, another way: The total area from \(z =-\infty\) to \(z = 0\) is \(0.5\), and the area from \(z=-\infty\) to \(z=-1.30\) is \(0.0968\). The area of the shaded region (from \(z=-1.30\) to \(z = 0\)) is \(0.5-0.0968 = 0.4032\). But wait, maybe there's a mis - interpretation. If we consider the fact that the area from \(z=-1.30\) to \(z=\infty\) is \(1 - 0.0968=0.9032\).
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D. \(0.9032\)