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Question
find the area of the figure. (sides meet at right angles.)
\\(\text{cm}^2\\)
Calculate the area of the outer bounding rectangle
$$
A_{\text{outer}} = 10 \text{ cm} \times 6 \text{ cm} = 60 \text{ cm}^2
$$
Calculate the area of the missing top-middle rectangular cutout
$$
A_{\text{cutout}} = 4 \text{ cm} \times 3 \text{ cm} = 12 \text{ cm}^2
$$
Subtract the cutout area from the outer rectangle area
$$
A_{\text{figure}} = 60 \text{ cm}^2 - 12 \text{ cm}^2 = 48 \text{ cm}^2
$$
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Find the area of the figure. (Sides meet at right angles.)
<blank>48</blank> \(\text{cm}^2\)