Question

find the area of the figure below, composed of a rectangle with two semicircles removed. round to the nearest tenths place. 9 4 answer attempt 1 out of 2 submit answer

Explanation:

Step1: Calculate the area of the rectangle

The formula for the area of a rectangle is \(A_{rectangle}=length\times width\). Here, the length \(l = 9\) and the width \(w=4\). So, \(A_{rectangle}=9\times4 = 36\).

Step2: Calculate the area of the two - semicircles (equivalent to one full circle)

The formula for the area of a circle is \(A_{circle}=\pi r^{2}\). Given the diameter \(d = 4\), then the radius \(r=\frac{d}{2}=\frac{4}{2}=2\). So, \(A_{circle}=\pi\times(2)^{2}=4\pi\approx4\times 3.14 = 12.56\).

Step3: Calculate the area of the composite figure

The area of the figure \(A=A_{rectangle}-A_{circle}\). Substitute the values: \(A = 36-12.56=23.44\approx23.4\).

Answer:

\(23.4\)