Question

find the acceleration of the 1kg block represented in the following free body diagram
hint: calculate first the net force.
find the acceleration of the 1kg block m the following diagram.
answer: type your answer... choose your answer...

Explanation:

Step1: Calculate the net force in the horizontal direction

The forces in the horizontal direction are \(5N\) (to the right) and \(5N\) (to the left). Using the formula \(F_{net,x}=F_1 + F_2\), where \(F_1 = 5N\) and \(F_2=- 5N\). So \(F_{net,x}=5N+( - 5N)=0N\)

Step2: Calculate the net force in the vertical direction

The only vertical force is \(F = 4N\) (down - ward). Let the mass \(m = 1kg\). According to Newton's second law \(F = ma\), where \(F\) is the net force, \(m\) is the mass and \(a\) is the acceleration.
We know \(F = 4N\) and \(m = 1kg\). Rearranging the formula \(a=\frac{F}{m}\)
Substitute \(F = 4N\) and \(m = 1kg\) into the formula: \(a=\frac{4N}{1kg}\)

Answer:

\(4m/s^{2}\) (in the downward direction)