Question

final grade an instructor grades exams, 50%; term paper, 20%; and final exam, 30%. a student had grades of 90, 91, and 96, respectively, for exams, term paper, and final exam. find the student’s final average. use the weighted mean. the student’s final average is \boxed{}.

Explanation:

Step1: Recall weighted mean formula

The weighted mean formula is $\bar{x} = \sum (w_i \cdot x_i)$, where $w_i$ are the weights (as decimals) and $x_i$ are the values. Here, weights are 0.5 (50%), 0.2 (20%), 0.3 (30%) and values are 90, 91, 96.

Step2: Calculate each weighted term

• For exams: $0.5 \cdot 90 = 45$
• For term paper: $0.2 \cdot 91 = 18.2$
• For final exam: $0.3 \cdot 96 = 28.8$

Step3: Sum the weighted terms

Add the three results: $45 + 18.2 + 28.8 = 92$

Answer:

92