Question

fill in the \\(y\\) values of the t-table for the function \\(y = \sqrt3{x}\\).

\\(\

$$\begin{array}{c|c} x & y \\\\ \\hline -8 & \\\\ -1 & \\\\ 0 & \\\\ 1 & \\\\ 8 & \\end{array}$$

\\)

this is the graph of the function: \\(y = \sqrt3{x}\\)

Explanation:

Identify the function and inputs

The given function is:

$$y = \sqrt[3]{x}$$

We need to evaluate this function for the following \(x\)-values:

$$x \in \{-8, -1, 0, 1, 8\}$$

Evaluate for negative inputs

Using the properties of odd roots, we calculate:

• For \(x = -8\):

$$y = \sqrt[3]{-8} = -2$$

• For \(x = -1\):

$$y = \sqrt[3]{-1} = -1$$

Evaluate for zero and positive inputs

We calculate the remaining values:

• For \(x = 0\):

$$y = \sqrt[3]{0} = 0$$

• For \(x = 1\):

$$y = \sqrt[3]{1} = 1$$

• For \(x = 8\):

$$y = \sqrt[3]{8} = 2$$

Answer:

Fill in the \(y\) values of the t-table for the function \(y = \sqrt[3]{x}\).

\(x\)	\(y\)
\(-1\)	<blank>-1</blank>
\(0\)	<blank>0</blank>
\(1\)	<blank>1</blank>
\(8\)	<blank>2</blank>