Question

1. in the figure, the triangles are similar. what is the distance d from the senior high to the junior high? round to the nearest tenth.

Explanation:

Step1: Set up the proportion

Since the triangles are similar, the ratios of corresponding sides are equal. So, $\frac{d}{129}=\frac{30}{210}$.

Step2: Solve for \(d\)

Cross - multiply: $210d = 129\times30$. Then $210d=3870$. Divide both sides by 210: $d=\frac{3870}{210}$.

Step3: Calculate the value

$d=\frac{3870}{210}=18.42857\cdots$. Rounding to the nearest tenth.

Answer:

$18.4$ km