Question

on a ferris wheel, what happens to the speed and torque? speed decreases; torques increases speed increases; torques increases speed decreases; torques decreases speed increases; torques decreases

Explanation:

On a Ferris wheel, as the wheel rotates, the speed of the passengers (tangential speed) remains relatively constant (assuming the Ferris wheel is rotating at a steady rate). However, the torque (rotational force) required to keep the Ferris wheel moving can change depending on factors like the distribution of mass (passengers) around the wheel. If more mass is concentrated at a certain point, more torque may be needed to maintain rotation. But in a typical, evenly - loaded Ferris wheel, if we consider the basic relationship \(T = F\times r\) (torque \(T\), force \(F\), radius \(r\)) and \(v=\omega r\) (linear speed \(v\), angular speed \(\omega\), radius \(r\)), if the Ferris wheel is designed to rotate at a constant angular speed \(\omega\), the linear speed \(v\) is constant. But if there are changes in the load (e.g., passengers getting on and off unevenly), torque requirements can change. In a normal, steady - state operation with even loading, if we assume some idealized model, if the speed is constant (as in a well - maintained Ferris wheel running at a set rotational rate), but if we consider a non - ideal case where, for example, starting from rest (speed increases from 0), torque is high initially to overcome inertia. But in the context of the given options, if we assume a situation where, say, due to some mechanical issue or change in load:

• If speed decreases (less linear speed for a given radius, which could imply lower angular speed if radius is constant), and if there is a need to maintain rotation (e.g., against some increased resistance), torque might increase (as more force is needed at the same radius to maintain rotation).

Answer:

Speed decreases; torques increases