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fall 2025 geometry b wwva solving for side lengths of right triangles w…

Question

fall 2025 geometry b wwva solving for side lengths of right triangles which equation can be used to solve for b? tan(30°) = 5/b tan(30°) = b/10 tan(30°) = b/5

Explanation:

Step1: Recall tangent - ratio definition

In a right - triangle, $\tan\theta=\frac{\text{opposite}}{\text{adjacent}}$. For angle $A = 30^{\circ}$ in right - triangle $ABC$, the opposite side to angle $A$ is $BC = 5$ cm and the adjacent side is $AC=b$.

Step2: Apply the tangent formula

We know that $\tan(A)=\frac{BC}{AC}$. Substituting $A = 30^{\circ}$, $BC = 5$ cm and $AC = b$ into the formula, we get $\tan(30^{\circ})=\frac{5}{b}$.

Answer:

$\tan(30^{\circ})=\frac{5}{b}$