Question

fall 2025 geometry b wwva solving for side lengths of right triangles which equation can be used to solve for c? c = 5 / sin(35°) c = 5 / cos(35°) c = (5)sin(35°)

Explanation:

Step1: Recall sine - cosine definitions in right - triangle

In a right - triangle, $\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}$ and $\cos\theta = \frac{\text{adjacent}}{\text{hypotenuse}}$. Given angle $B = 35^{\circ}$, the side opposite to angle $B$ is $c$ and the hypotenuse is $5$.

Step2: Apply the sine formula

We know that $\sin B=\frac{c}{5}$, where $B = 35^{\circ}$. Rearranging the formula $\sin(35^{\circ})=\frac{c}{5}$ for $c$, we get $c = 5\sin(35^{\circ})$.

Answer:

$c=(5)\sin(35^{\circ})$