Question

the fair spinner shown is spun 2 times. the set of possible outcomes are: s = {rr, bb, yy, gg, rb, br, ry, yr, rg, gr, by, yb, bg, gb, yg, gy} the number of yellows in the outcome is summarized in the table on the right. using the data from the theoretical probability table, what is the probability of the spinner landing only once on yellow in two spins? 0.0625 0.5625 0.375 1

Explanation:

Step1: Calculate total number of spins

Total number of spins \(=9 + 6+1=16\)

Step2: Calculate probability

Probability \(P=\frac{\text{Frequency of 1 yellow}}{\text{Total number of spins}}=\frac{6}{16}\)
Simplify \(\frac{6}{16}=\frac{3}{8}=0.375\)

Answer:

\(0.375\)