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Question
factoring the gcf from a polynomial
what is the factored form of the polynomial \\(27x^2y - 43xy^2\\)?
\\(xy(27x - 43y)\\)
\\(x^2y^2(27 - 43)\\)
\\(3xy(9x - 17y)\\)
\\(3x^2y(9 - 14y)\\)
Find the GCF of the coefficients
$$
\gcd(27, 43) = 1
$$
Find the GCF of the variable parts
$$
\gcd(x^2y, xy^2) = xy
$$
Factor out the GCF from the polynomial
$$
27x^2y - 43xy^2 = xy(27x - 43y)
$$
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- (A) \(xy(27x - 43y)\) (Correct answer)
- (B) \(x^2y^2(27 - 43)\)
- (C) \(3xy(9x - 17y)\)
- (D) \(3x^2y(9 - 14y)\)