Question

factor the trinomial.

\\11u^3v - 30u^2v^2 + 16uv^3 = \\

Explanation:

Factor out the greatest common factor

$$ 11u^3v - 30u^2v^2 + 16uv^3 = uv(11u^2 - 30uv + 16v^2) $$

Factor the remaining quadratic trinomial

$$ 11u^2 - 30uv + 16v^2 = (11u - 8v)(u - 2v) $$

Combine the factored components

$$ 11u^3v - 30u^2v^2 + 16uv^3 = uv(11u - 8v)(u - 2v) $$

Answer:

Factor the trinomial.

$$11u^3v - 30u^2v^2 + 16uv^3 =$$

<blank>\(uv(11u - 8v)(u - 2v)\)</blank>