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factor completely. $4f^2 - 25$

Question

factor completely.
$4f^2 - 25$

Explanation:

Step1: Identify the form

The expression \(4f^2 - 25\) is a difference of squares. The formula for factoring a difference of squares is \(a^2 - b^2=(a + b)(a - b)\). Here, \(a = 2f\) (since \((2f)^2=4f^2\)) and \(b = 5\) (since \(5^2 = 25\)).

Step2: Apply the formula

Using the difference of squares formula \(a^2 - b^2=(a + b)(a - b)\) with \(a = 2f\) and \(b = 5\), we get \((2f + 5)(2f - 5)\).

Answer:

\((2f + 5)(2f - 5)\)