Question

factor completely.
$10v^3 + 4v^2 - 10v - 4$

Explanation:

Step1: Group terms into pairs

$(10v^3 + 4v^2) + (-10v - 4)$

Step2: Factor out GCF from each pair

$2v^2(5v + 2) - 2(5v + 2)$

Step3: Factor out common binomial

$(5v + 2)(2v^2 - 2)$

Step4: Factor out GCF from the second term

$(5v + 2) \cdot 2(v^2 - 1)$

Step5: Factor difference of squares

$2(5v + 2)(v - 1)(v + 1)$

Answer:

$2(5v + 2)(v - 1)(v + 1)$