Question

for the expressions \\(\frac{a}{b}\\) and \\(a + b\\), choose values for \\(a\\) and \\(b\\) so that \\(\frac{a}{b}\\) is positive and \\(a + b\\) is negative.\
\\(\

$$\begin{array}{|c|c|}\\hline a & b \\\\ \\hline & \\\\ \\hline\\end{array}$$

\\)

Explanation:

Step1: Set sign condition for $\frac{a}{b}$

For $\frac{a}{b}>0$, $a$ and $b$ must have the same sign (both positive or both negative).

Step2: Set sign condition for $a+b$

For $a+b<0$, the sum of $a$ and $b$ must be negative. Since same-sign pairs: if both positive, sum is positive (invalid); so both must be negative, with their sum negative.

Step3: Pick valid negative values

Choose $a=-3$, $b=-2$. Check: $\frac{-3}{-2}=\frac{3}{2}>0$, $-3+(-2)=-5<0$.

Answer:

$a$	$b$

(Note: Any pair of negative integers/numbers where their sum is negative is valid, e.g., $a=-4, b=-1$ also works.)