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Question
express sin q as a fraction in simplest terms.
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attempt 1 out of 2
sin q =
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right triangle with right angle at p, po = 12, pq = 5, oq = 13
Step1: Recall Sine Definition
In a right triangle, $\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}}$.
Step2: Identify Sides for $\angle Q$
For $\angle Q$, the opposite side to $Q$ is $OP = 12$, and the hypotenuse is $OQ = 13$.
Step3: Calculate $\sin Q$
Using the sine formula: $\sin Q = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{12}{13}$.
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$\frac{12}{13}$