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Question
explain why the null hypothesis $h_0: \mu_1 = \mu_2$ is equivalent to the null hypothesis $h_0: \mu_1 - \mu_2 = 0$.
choose the correct answer below.
a. they are equivalent through algebraic manipulation.
b. they are equivalent because the null hypothesis, $h_0$, is always assumed to be true.
c. the values of $\mu_1$ and $\mu_2$ are equivalent in every population. therefore, these hypotheses are equivalent.
d. by definition, the null hypothesis is always equal to 0. therefore, these hypotheses are equivalent.
To determine why \( H_0: \mu_1 = \mu_2 \) is equivalent to \( H_0: \mu_1 - \mu_2 = 0 \), we analyze the options:
- Option A: Subtract \( \mu_2 \) from both sides of \( \mu_1 = \mu_2 \), resulting in \( \mu_1 - \mu_2 = 0 \). This is algebraic manipulation, so this option is correct.
- Option B: The null hypothesis being "assumed true" does not explain their equivalence.
- Option C: \( \mu_1 \) and \( \mu_2 \) are not necessarily equivalent in every population (the null hypothesis is a claim to test, not a universal truth).
- Option D: The null hypothesis is not "always equal to 0"—it depends on the claim (e.g., \( H_0: \mu_1 = \mu_2 \) is a valid null hypothesis without being 0 in form).
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A. They are equivalent through algebraic manipulation.