Question

expand the expression using the binomial theorem:

\\((2x - 1)^3 = \box x^3 + \box x^2 + \box x^1 + \box\\)

Explanation:

Step1: Apply the Binomial Theorem formula

$$(a + b)^3 = a^3 + 3a^2b + 3ab^2 + b^3$$

Step2: Substitute the given terms into the formula

$$(2x - 1)^3 = (2x)^3 + 3(2x)^2(-1) + 3(2x)(-1)^2 + (-1)^3$$

Step3: Simplify each term of the expansion

$$(2x - 1)^3 = 8x^3 - 12x^2 + 6x^1 - 1$$

Answer:

\(8\), \(-12\), \(6\), \(-1\)