Question

6.g.1 exit ticket
write the formulas in the lines below:

1. triangle

a =

1. rectangle

a =

1. square

a =

1. parallelogram

a =
find the area of each shape below

Explanation:

Step1: Recall area formulas

1. For a triangle, the area formula is $A=\frac{1}{2}bh$, where $b$ is the base and $h$ is the height.
2. For a rectangle, the area formula is $A = lw$, where $l$ is the length and $w$ is the width.
3. For a square, since all - sides are equal, if the side length is $s$, the area formula is $A=s^{2}$.
4. For a parallelogram, the area formula is $A = bh$, where $b$ is the base and $h$ is the height.

Step2: Calculate areas of given shapes

Triangle:

Given base $b = 10$ cm and height $h = 8$ cm. Using the formula $A=\frac{1}{2}bh$, we have $A=\frac{1}{2}\times10\times8=40$ $cm^{2}$.

Rectangle:

Given length $l = 4.5$ ft and width $w = 2$ ft. Using the formula $A=lw$, we get $A = 4.5\times2=9$ $ft^{2}$.

Square:

If the side - length $s=\frac{1}{2}$ ft, using the formula $A = s^{2}$, we have $A=(\frac{1}{2})^{2}=\frac{1}{4}$ $ft^{2}$.

Parallelogram:

Given base $b = 10$ ft and height $h = 8$ ft. Using the formula $A = bh$, we obtain $A=10\times8 = 80$ $ft^{2}$.

Answer:

1. Triangle formula: $A=\frac{1}{2}bh$; Area: $40$ $cm^{2}$
2. Rectangle formula: $A = lw$; Area: $9$ $ft^{2}$
3. Square formula: $A=s^{2}$; Area: $\frac{1}{4}$ $ft^{2}$
4. Parallelogram formula: $A = bh$; Area: $80$ $ft^{2}$