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if f(x) is an even function and (6, 8) is one the points on the graph o…

Question

if f(x) is an even function and (6, 8) is one the points on the graph of f(x), which reason explains why (-6, 8) must also be a point on the graph?

since the function is even, the outputs of a negative x - value and a positive x - value are the same.

since the function is even, the outputs of a negative y - value and a positive y - value are the same.

the graph has rotational symmetry, so the point will be reflected across the y - axis.

the graph has rotational symmetry, so the point will be rotated 90 degrees about the origin.

Explanation:

Brief Explanations
  1. Recall the definition of an even function: For an even function \( f(x) \), \( f(-x)=f(x) \) for all \( x \) in the domain. This means that if \( (a, b) \) is on the graph (so \( f(a) = b \)), then \( f(-a)=b \), so \( (-a, b) \) is also on the graph. In other words, the output (y - value) for \( -x \) is the same as the output for \( x \).
  2. Analyze the options:
  • Option 1: "Since the function is even, the outputs of a negative x - value and a positive x - value are the same." This matches the definition of an even function. If \( x = 6 \) gives \( f(6)=8 \), then \( x=- 6 \) gives \( f(-6)=f(6) = 8 \), so \( (-6,8) \) is on the graph.
  • Option 2: Even functions are about the relationship between \( f(x) \) and \( f(-x) \), not about negative and positive y - values. So this option is incorrect.
  • Option 3: Even functions have reflection symmetry about the y - axis, not rotational symmetry. Rotational symmetry is a property of odd functions (rotation by 180 degrees about the origin) or other types of functions, not even functions. So this option is incorrect.
  • Option 4: Even functions do not have 90 - degree rotational symmetry about the origin. This is not a property of even functions. So this option is incorrect.

Answer:

A. Since the function is even, the outputs of a negative x - value and a positive x - value are the same.