Question

evaluate the following function at the indicated values.

\\h(x)=2^x\\

(a) \\(h(-5)\\)

(b) \\(h(0)\\)

(c) \\(h(4)\\)

Explanation:

Evaluate the function at x = -5

Using the Function Evaluation and Exponential Functions knowledge points

$$ H(-5) = 2^{-5} = \frac{1}{2^5} = \frac{1}{32} $$

Evaluate the function at x = 0

Using the Function Evaluation and Exponential Functions knowledge points

$$ H(0) = 2^0 = 1 $$

Evaluate the function at x = 4

Using the Function Evaluation and Exponential Functions knowledge points

$$ H(4) = 2^4 = 16 $$

Answer:

Evaluate the following function at the indicated values.

$$H(x)=2^x$$

(a) \(H(-5)\)
<blank>\(\frac{1}{32}\)</blank>

(b) \(H(0)\)
<blank>1</blank>

(c) \(H(4)\)
<blank>16</blank>