Question

evaluate the expressions.
your answer
$-left(\frac{2}{9}
ight)^{0}=-1$
$7^{0}=1$

Explanation:

Step1: Recall zero - exponent rule

Any non - zero number to the power of 0 is 1. That is, for any real number $a
eq0$, $a^{0}=1$.

Step2: Evaluate $-(\frac{2}{9})^{0}$

Since $\frac{2}{9}
eq0$, $(\frac{2}{9})^{0} = 1$. Then $-(\frac{2}{9})^{0}=-1$.

Step3: Evaluate $7^{0}$

Since $7
eq0$, $7^{0}=1$.

Answer:

$-(\frac{2}{9})^{0}=-1$, $7^{0}=1$