Question

this equation can be rearranged to a different form which includes momentum (\\(\vec{p}\\)).
drag and match each equation to the step that produces it.

if an object experiences a nonzero net force, what can we conclude about its momentum?

Explanation:

Step1: Recall Newton's second law in terms of momentum

Newton's second law can be written as \(\sum\vec{F}=\frac{\Delta\vec{p}}{\Delta t}\), where \(\vec{p} = m\vec{v}\) is the momentum.

Step2: Analyze the effect of non - zero net force

If \(\sum\vec{F}
eq0\), then from \(\sum\vec{F}=\frac{\Delta\vec{p}}{\Delta t}\), we can multiply both sides by \(\Delta t\) (assuming \(\Delta t> 0\)) to get \(\Delta\vec{p}=\sum\vec{F}\Delta t\). Since \(\sum\vec{F}
eq0\) and \(\Delta t>0\), \(\Delta\vec{p}
eq0\).

Answer:

The momentum of the object is changing.