Question

the equation of a linear function in point-slope form is $y - y_1 = m(x - x_1)$. harold correctly wrote the equation $y = 3(x - 7)$ using a point and the slope. which point did harold use?
$\bigcirc\\ (7, 3)$
$\bigcirc\\ (0, 7)$
$\bigcirc\\ (7, 0)$
$\bigcirc\\ (3, 7)$

Explanation:

Step1: Recall point - slope form

The point - slope form of a linear equation is $y - y_1=m(x - x_1)$, where $(x_1,y_1)$ is a point on the line and $m$ is the slope.
We are given the equation $y = 3(x - 7)$. We can rewrite this equation in the form $y-0=3(x - 7)$ (by subtracting 0 from $y$ and keeping the right - hand side as it is).

Step2: Identify the point

Comparing $y - y_1=m(x - x_1)$ with $y-0 = 3(x - 7)$, we can see that $x_1 = 7$ and $y_1=0$. So the point $(x_1,y_1)$ is $(7,0)$.

Answer:

(7, 0)