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QUESTION IMAGE

enter the measure of the angle. degrees

Question

enter the measure of the angle. degrees

Explanation:

Step1: Assume angle GCJ is \(7x\) and angle JCE is \(5x\), and angle GCE is a right angle (90°) (since it looks like a right angle from the diagram, so \(7x + 5x=90\))

\(7x + 5x = 90\)

Step2: Combine like terms

\(12x = 90\)

Step3: Solve for x

\(x=\frac{90}{12}=\frac{15}{2} = 7.5\)

Step4: Find angle GCJ (7x)

\(7\times7.5 = 52.5\) (If we need angle JCE, it's \(5\times7.5 = 37.5\); but since the input box is near J, maybe angle GCJ? Wait, maybe the diagram has angle GCJ and JCE adding to 90. Wait, maybe I misread. Wait, maybe the angle at C between G and J is \(7x\) and between J and E is \(5x\), and angle GCE is 90. So total \(12x = 90\), x=7.5. Then if we need angle GCJ (7x) is 52.5, or JCE (5x) is 37.5. Wait, maybe the problem is to find angle GCJ or JCE? Wait, the input box is for the angle, maybe angle GCJ? Let's check.

Wait, maybe the diagram is a right angle, so sum of \(7x\) and \(5x\) is 90. So solving:

\(7x + 5x = 90\)

\(12x = 90\)

\(x = 7.5\)

Then if the angle is \(7x\), it's \(7\times7.5 = 52.5\); if \(5x\), it's \(37.5\). Wait, maybe the angle is angle GCJ (7x) or JCE (5x). Wait, the input box is near J, so maybe angle GCJ? Let's confirm.

Wait, maybe the diagram shows that GC is a horizontal line, JC is a line, and EC is a vertical line, making angle GCE 90 degrees. So angle between GC and JC is \(7x\), between JC and EC is \(5x\), so total 90. So solving for x, then finding the angle. Let's proceed with angle GCJ (7x):

\(7x = 7\times7.5 = 52.5\)

Or angle JCE: \(5x = 37.5\)

Wait, maybe the problem is to find angle GCJ. Let's go with that.

Answer:

52.5 (or 37.5 if it's angle JCE; but based on the diagram's input box near J, maybe angle GCJ is 52.5)